Solutions Available. Question: Prob 3. Transcribed image text: Problem #1 A W12 x 72 is used as a column having an unsupported height of 4. 0 and Γ = 210 60 0 60 90 0 0 0 0 , and given the fact that Pie Traynor’s risky portfolio is split 50-50 be- tween two risky assets: (a) Which security of the three must be the risk-free asset? Why? (b) Calculate the expected return and standard. H. What are the nominal and actual depths of a W12 ×336 wide-flange member? Compare these to the nominal and actual depths of a W12×16. Homework_Assignment_3. 1. Civil Engineering questions and answers. Close suggestions Search Search. (Hint: Use your AISC Manual. MATH 1342. You should refer to. Khan Department of Economics University of Waterloo Winterhomework. Safety-related parameters MTTFD 826 years DCavg 0 % 2 PHOTOELECTRIC SENSORS | SICK Product data sheet | 2023-07-11 13:54:49 Subject to change without. 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First of all, all of them are highly skilled professionals and have higher academic degrees like Masters and PhDs. (35 points) Select a lightest 30-fl-long W12 section of A992 steel to support a tensile service dead load is 130 kips and a tensile service live load is 110 kips. Exercise1 Q. New Jersey Institute Of Technology. QUESTION # 1 Select the lightest W12 section (A992 steel) for a member resisting a tensile force of 560 k. Integrated Chinese workbook homework answers. Finished Papers. Linguistics of American Sign Language, 5th Ed. pdf from CSCI 358 at Colorado School of Mines. Important! As outlined in the course syllabus thisThe W12 × 50 is rade of A 982 steel and is used as a colurn that has a length of 18. Using the university data views from the W12 Assignment: University Project - NON-NORMALIZED DATA, create a. 3-7. 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This exquisite Edwardian single-family house has a 1344 Sqft main…. If both are possi ble, circle. question: 4) a w12 x 58 wide flange beam is used as a if both ends are pinned, column 30 ft tall. 15. Identified Q&As 58. Search Search Search done loading. ece414_hw2_w12. 0 ksi and the allowable shear stress is Tallow=12 ksi. Show all details (a) Determine the Shear Lag Factor U (b) Determine the Effective Area A (c) Determine the design tensile. (Figure 1) Determine the deflection of the beam at its center C. Take into the capacity that our suppliers had. 9/5. The allowable bending stress is Oollow = 22 ksi, and the allowable shear stress is Tallow = 12 ksi.