I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. Expressions can contain only one hint. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. format_datetime(timestamp, format) → varchar. How can I calculate the date difference between these 2 columns? sql; sql-server-2008; t-sql; datediff. To answer your question to find all records that occurred last month. Tip. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. * FROM #HRAL h INNER JOIN #LAZY_DATE_DIM dd ON dd. Then, it converts that result to a date, using the format 'yyyy-MM-dd'. 25) This seems to be another common approach - and was also given in a comment on my question. Viewed 110k times 49 I have a table with following structure. v_interval := p_end_date - p_start_date + 1; -- calculate total number of days between dates, including start and end dates. S is milliseconds in one or up to six digits. The Oracle NEXT_DAY() function returns the date of the first weekday specified by day name that is later than a date. The numbers to the left of the decimal point are the days, the numbers to the right is the decimal fraction. Share. MONTHS_BETWEEN returns number of months between dates date1 and date2. SELECT DATEADD ( quarter, DATEDIFF. StartDate, SYSDATE) you would use: MONTHS_BETWEEN(pr. 4193548 The number of whole months can be split into. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. SQL Querying by a specific month. You don't need to generate all the days as it'll be inefficient; just use a recursive sub-query factoring clause to iterate over each month: WITH months (. Date ) AS NextDate FROM. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. I would like to select 1 if current date falls between 2 dates through Oracle SQL. YEAR: Stores the year information only, either in 2-digit or 4-digit format. Another example using the. The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. this will be add to 1900-01-01 , but only the months. SELECT TO_DATE (“2021-01-15”) as “Date value”; TO_CHAR. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. Teams. If year numbers are different calculation of 52 * year difference + week number. Must be a date, a time, a timestamp, or an expression that can be evaluated to a date, a time, or a timestamp. Oracle GoldenGate add trandata errors. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. MySQLには MONTH 機能がありますが、Oracleにはありません。 存在しない関数 DATEDIFF が無効なIDであるのと 同じ理由。 ORA-00904の解決策は、 EXTRACTという名前の正しいOracle関数 を呼び出して、列の月の値を取得することです。Use DATEADD and DATEDIFF() function together in SQL query. The integer value represents the day and the fractional value represents the. startdate)-1 as [Datediff] from #temp e1 join #temp e3. Must be one of the values listed in Supported Date and Time Parts (e. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). You cannot mix xdofx statements with XSL expressions in the same context. add_months (date,n) Returns the date that corresponds to date plus the number of months indicated by the integer n . Date > T1. DATEDIFF(expr1,expr2) DATEDIFF() は、ある日付から別の日付までの日数の値として表現された expr1 − expr2 を返します。expr1 および expr2 は、日付または日付時間式です。 値の日付部分のみが計算に使用されます。One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. COMPUTE days3 = CTIME. The Stored Procedure accepts two inputs - A start date and end date of the date range desired by the user. The int data type takes 4 bytes as storage size whereas. There are two methods to achieve this. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. oracle; datediff; or ask your own question. 14. Improve this answer. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. We would like to show you a description here but the site won’t allow us. StandardDeviationPopulation(group. sql. This function is used to get the timestamp value from the specified character string. INTERVAL '15. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. select trunc (months_between (:end_date,. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. I have a table where PurchasedDate is maintained. 0. This function is not sensitive to the NLS_CALENDAR session parameter. lastModified - w. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. The return type is always DATE, regardless of the datatype of date. What this allows you to do is pass in two TIMESTAMP or DATETIME values (or even DATE as MySQL will auto-convert) as well as the unit of time you want to base your difference on. The DATEDIFF() function returns the number of days between two date values. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. 365 days elapse between the two dates. Then it would also be helpful to be able to. January 30, 2004 - 7:26 pm UTC. Share. 3. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. Do this even for a single day—e. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. Beneath the plainness of its name, it hides a little depth. enddate, e3. Syntax. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. %DateAdd . Syntax: TIMESTAMPADD (interval, expr, timestamp) Example:. January 30, 2004 - 7:26 pm UTC. In SQL Server, it could be something like this: DELETE FROM table WHERE DATEDIFF(month, load_timestamp, GETDATE()) > 13; It would be slightly different in each database – not all of them have a DATEDIFF function. Modified 1 year, 8 months ago. This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. Here's how it does this: First the DATE function creates the date, 5/1/2016. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. Was this tutorial helpful? Previously Oracle ROW_NUMBER Up Next Oracle ADD_MONTHS This tutorial provides you with the most commonly used Oracle date. After executing the above query, we got the following output: SHOW_DAY. datediff (q,start date,end date) i. To break the diff between 2 dates into days, hours, minutes, sec -- you can use the following: Dy gives you number of days between 2 dates (partial days discarded). @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. columns c puts a limit on how many dates are returned. Kindly tell me how to calculate age as in years month days. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 DateDiff is not a function that exists in Oracle. Oracle SQL Hours Difference between dates in HH:MM:SS. Another example is to get the month of. Table 7-13 Date Format Models for the ROUND and TRUNC Date Functions. One truncates a date to the precision specified (kind of like rounding, in a way) and the other just returns a particular part of a datetime. Hi tom, I want day, month, minute and years difference everyting in seconds. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . To compare dates in SQL, the most common functions used are DATEDIFF, DATE_ADD, DATE_SUB, and NOW. MONTHS_BETWEEN: Returns an estimate of the number of months between expression1 and expression2. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. The screenshot below shows the data I want as well as the incorrect month between results I am obtaining. 65. You can use this to fetch all the days between two dates by: Subtracting the first date from the last to get the number of days. columns. 1 - Find the total months count till today's date using DATEDIFF function -. ArrivalDate, Trips. One option that avoids needing to add EndDate + 23:59:59. 1. MONTHS_BETWEEN gives the number of whole months between the 2 dates, and calculates the fractional part as the remainder in days divided by 31. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. Examples of Results in Months. E. For example, between those dates: "03/03/2020 - 06/06/2020" I need something like "(03,04,05,06)". The default is zero (0). DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. here i am trying get the month differences between two. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. Two dates to calculate the number of days between. 3. The unit of time. Option 1. Asked 10 years, 2 months ago. two full prior months plus the current partial month. 1. DateAdd. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. The Overflow Blog An intuitive introduction to text embeddings. The %DateAdd meta-SQL function returns a date by adding add_days to date_from. 6. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. The difference between 1st March 2011 and 29th February 2012 is 0. 1. 0 months apart:Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. 1. It is the unit in which the DATEDIFF() function returns the difference between a start date and an end date e. The key is to use DATEADD and DATEDIFF along with the appropriate SQL timespan enumeration. Using DbFunctions, accessed via EF. . Functions. ArrivalDate, Trips. for extended XSL functions. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. Then Oracle will not use an index on the date_column and would need a separate function-based index on either TRUNC(date_column) or TO_CHAR(date_column, 'DD-MM-YYYY'). The application passes in two parameters: a string representing the number of the desired month (i. Its seems that "DATEADD ": invalid identifier. 1. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). 0 and later Information in this document applies to any platform. 7 Date and Time Functions. Currently I am only returning 1. Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. Thus your AGE ('2019-12-01', '2018-12. SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Edit the SQL Statement, and click "Run SQL" to see the result. Dte <= @gapPeriod; --only older records. The result is formatted according to the Format parameter. Again, the expected results would be a value of 1. 8. ) Description It's easy to do date arithmetic in Oracle Database, but it can be hard to remember the formulas. Hot. ToDate)); My SQL to LINQ Recipe might help you with some translation issues in the future. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. Return the current time. Run SQL ». EXECUTION_DATE, EXEC_DIFF 01-FEB-13, 1 31-JAN-13, 2 30-JAN-13, 2. Our SQL tutorial will teach you how to use SQL in: MySQL, SQL Server, MS Access, Oracle, Sybase, Informix, Postgres, and other database systems. Date parts examples are day, week,. DAYS function. date_part is the part of. , SYSDATE - pr. 3 Answers. Syntax DATEDIFF (datepart ,startdate ,enddate) datepart Abbreviations year. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. Improve this answer. From the documentation: date_part (): The date_part function is modeled on the traditional Ingres equivalent to the SQL-standard function extract:Date/time functions. Modified 7 years, 2 months ago. Also, you can check this for minutes : Oracle : how to subtract two dates and get minutes of the result. Hi tom, I want day, month, minute and years difference everyting in seconds. You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365. SELECT SYSDATE AS "Date" FROM DUAL; SYSDATE returns the system date and time but does not display the time unless formatted to do so with the function TO_CHAR (): SELECT TO_CHAR (SYSDATE,. 25)) AS `numberofemployees`. February 28 and March 28) and when the days of the month are the last day of the month (e. INTERVAL '15' MINUTE. 2. There are several date functions (DATENAME, DATEPART, DATEADD, DATEDIFF, etc. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. date. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. 在本文中，我们介绍了oracle数据库中的datediff函数。通过指定日期部分、开始日期和结束日期，我们可以使用datediff函数计算两个日期之间的差异。这对于计算日期之间的天数、小时数、分钟数等非常有用。希望本文对您理解datediff函数的使用有所帮助。 MySQL DATEDIFF: Calculating weeks, months, or years between two dates. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. Month difference between two dates in sql server. Share. Because the precision is 3, the fractional second ‘6789’ is rounded to ‘679’. Usage Notes¶. But your query is giving the last date of previous month. For many values of the local settings, this would simply fail. If you subtract from one date other you will get a count of days between this two dates. mm is a two digits of minute (00 through 59). SELECT to_char ( your_date_column, your_format_mask ) FROM your_table ORDER BY your_date_column. Syntax. How best can this be written? I need to use this in a where clause on DI Studio. Date2Date. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. Thanks in advance for any help; this has been driving us crazy for a few months now. join our newsletter and get access to exclusive content every month. Viewed 43k times 0 I want to. to get the date one second before midnight of. 1. SQL> ed Wrote file afiedt. Formats timestamp as a string using format. You also wouldn't prefix a function name with the @ sign. There are many tricks to generate rows in Oracle Database. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS. Oracle equivalent to SQL Server/Sybase. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. Feb-N to Mar-N is commonly accepted as a "month". g. Functions that return the current date or time each are evaluated only once per query at the start of query execution. This formula subtracts the first day of the ending month (5/1/2016) from the original end date in cell E17 (5/6/2016). Date 1: 10th March 2011. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters):. You can use the DateDiff function to determine how many specified time intervals exist between two dates. 7 months ago. As GMB has mentioned in the comment above, date functions depend on the database type you are using. It counts the number of year boundaries between two dates. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. ROUND (TO_NUMBER (END_DATE - START_DATE)) 小时：. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate Result: DiffDate 61 So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. ) and rest are two dates which you want to compare. Aug 17, 2021 at 11:13. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. Last 3 Months. Justin, the example which you gave, if that is the scenario I want the output as 1. 1 Answer. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. 0. Each Standard calendar week is defined to start on Sunday and it spans 7 days. The system calculates the number of complete months between given dates. DATEDIFF is built to return the number of date BOUNDARIES that are crossed. Here is an example that uses date functions. Problem. Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. 3. 1,984 1 1 gold badge 17 17 silver badges 31 31 bronze badges. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). So, this expression converts SYSDATE to a string, using whatever local settings are on your system. Q&A for work. months_between/120 = decades_between. Date manipulation is a common scenario when retrieving or storing data in a Microsoft SQL Server database. Select between two months. To create the rows, use the month generation technique above. However, The. MySQL :: MySQL 5. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. CREATE TABLE [table] ( ID int IDENTITY(1,1) PRIMARY KEY, Title nvarchar(20), Date date, Amount money. DateDiff ( date1, date2, date_part) パラメータ 説明; date1. CREATE FUNCTION trunc_date (@date DATETIME) RETURNS DATETIME AS BEGIN SELECT CONVERT (varchar, @date,112) END. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. Table 9. Modified 1 year, 8 months ago. DATE_ADD () Add time values (intervals) to a date value. Oracle PeopleSoft Tips and Tricks. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. Extract a value of a date time field e. 2903225806. Then you'll see the number. I see that marked final solution is not correct always. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. Based on the spreadsheet above, the following Excel function would return the following values:In Oracle, the datetime system function is SYSDATE. We’re calculating months of service in this example. DATEADD(datepart,number,date) The DATEPART() function is used to return a single part of a date/time, such as year, month, day, hour, minute, etc. Select(x => x. If date1 is earlier than date2 , then the result is negative. Improve this answer. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Again, the expected results would be a value of 1. Also, according to Oracle's documentation LAST_DAY returns a DATE. * 12 + (Extract(Month From CDate(EndDate)) - Extract(Month. This function adds N months to a date and returns the same day N month after. Share. For example, this function returns 1. user637544 Jun 1 2009 — edited Jun 1 2009. see this sqlfiddle. Parameter Description; date1, date2: Required. My DOB- 02-feb-1984 so my age should get as 27 Years 2 months 8 days How to do it. It’s a seven byte store of century, year, month, day and hour, minute and second. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. The function INTCK ('MONTH','31jan1991'd,'1feb1991’d) returns 1, because the two dates lie in different months that are one month apart. ROUND (TO_NUMBER (END_DATE - START_DATE) * 24) 分钟：. SHOW_DAY is an alias to store the day. If IsDate (startdate) and IsDate (enddate) Then. If you need to calculate minutes or seconds, you simply multiply the result by a constant: (date2 - date1)*1440 -- number of minutes (date2 - date1)*86400 -- number of seconds. You could, of course, write your own function and call that. MONTH, YEAR, WEEK, etc are not allowed for. PostgreSQL. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. I need to do rolling date select of the previous 18 months of data, not including the current month. SQL Server ignores that this is just one day. Write queries for continuous periods as explicit range condition. Concatenates a date to a time on either side of the + symbol and returns a TIMESTAMP or TIMESTAMPTZ. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. 利用日期间的加减运算. I have a creation date column in the table. 005479 (1 year + 2/365 years). See the following conditions: If date1 is later than date2, then the result is positive. ie if the month when the query is run is march 2013. SQL is a standard language for storing, manipulating and retrieving data in databases. The following shows the syntax of the DATEPART() function: DATEPART ( date_part , input_date ) Code language: SQL (Structured Query Language) (sql) The DATEPART() takes two arguments: date_part is the part of a date to be extracted. CODE = 'CONTACT_CLIENT' THEN a. Functions. event_id, evnt. Truncate a Date to a Specific Unit of Measure. FromDate, r. DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0) returns the beginning of next month. DatePart. So, we have to treat this type of cases too, which I usedMONTHS_BETWEEN = 1. If you are comparing to a date column in a existing table, then you need the date part too as you want to know December of which year was the previous month. then the following should be the result. DATEPART function is used to return a part of a given date in a numeric value. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. The result is formatted according to the Format parameter. The recommended solution on Stack Overflow for example is this. The second row is only 30 minutes apart, so the difference is 0. The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN( DATE '2017-07-01', DATE '2017-01-01') MONTH_DIFF FROM. SQL Query with Dates. BI Publisher has extended a set of SQL and XSL functions for use in RTF templates. 2903225806. For example, adding three months or 12 days to a starting date. mm is a two digits of minute (00 through 59). If date1 is earlier than date2 , then the result is negative. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. SELECT TIMESTAMPDIFF (MONTH, '2012-05-05', '2012-06-04') -- Outputs. +1 EndDate + 23:59:59. Gets the number of intervals between two DATE values. I used the following code: SELECT h. So, Feb-28 to Mar-28 is a month. The value returned is always of data type DATE, even if you specify a different datetime data type. The Oracle ROUND () function takes two arguments: 1) date. As Spark doesn't provide the other unit, I use below method, select (bigint (to_timestamp (endDate))) - (bigint (to_timestamp (startDate))) as time_diff. That prevents. Multiply the result of step 1 by 12 to transform it to months 3. DATEDIFF(MONTH, 0, GETDATE())-1, 0) AND DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1) based on the comment below I have modified the query. 2258064516 DATE_DIFF = 1. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. substr (to_char (to_date ('01-02-2018','mm-dd-yyyy'), <NLS_DATE_FORMAT>),4,3) The usual default value (for English-language versions of. 24. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46.